SOLUTION: The perimeter of a rectangle is 22ft the length is 3ft longer than the width. I need to know how to write a system of linear equation and then solve the resulting system.
X will b
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X will b
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Question 805645: The perimeter of a rectangle is 22ft the length is 3ft longer than the width. I need to know how to write a system of linear equation and then solve the resulting system.
X will be the length and y will be the width.
I know P=2L+2W
the perimeter is already given which is 22 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 22ft the length is 3ft longer than the width.
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L = W +3
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2(L+W) = 22
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Modify for elimination:
L - W = 3
L + W = 11
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Add and solve for "L";
2L = 14
L = 7
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Solve for "W"
L + W = 11
7 + W = 11
W = 4
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Cheers,
Stan H.
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