SOLUTION: Please help me solve this question: 33% of all pets sold at a pet store are dogs. One day, 8 people arrive at the store and purchase pets.(Note: One pet is purchased per person.)

Algebra ->  Probability-and-statistics -> SOLUTION: Please help me solve this question: 33% of all pets sold at a pet store are dogs. One day, 8 people arrive at the store and purchase pets.(Note: One pet is purchased per person.)       Log On


   



Question 805609: Please help me solve this question:
33% of all pets sold at a pet store are dogs. One day, 8 people arrive at the store and purchase pets.(Note: One pet is purchased per person.)
What is the probability that exactly 5 of them are dogs? If the store has only 6 dogs, what is the probability that they have sufficient dogs for sale that day?

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
33% of all pets sold at a pet store are dogs. One day, 8 people arrive at the )store and purchase pets.(Note: One pet is purchased per person.)
What is the probability that exactly 5 of them are dogs?
===============
Binomial Problem with n = 8 and p(dog bought) = 0.33
-----
P(x = 5) = 8C5(0.33)^5*(0.67)^3 = binompdf(8,0.33,5) = 0.0659
======
If the store has only 6 dogs, what is the probability that they have sufficient dogs for sale that day?
------
They can expect that 1/3 of their sales will be dogs.
=========
Cheers,
Stan H.