Question 805466: Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial p. Use the given values of n & p to find the mean and standard deviation. Also, use the range rule of thumb to find the minimum usual value mean - 2standard deviation and the maximum usual value mean + 2standard deviation. n = 150, p = 0.8
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial p. Use the given values of n & p to find the mean and standard deviation.
mean = np
std = sqrt(npq)
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Also, use the range rule of thumb to find the minimum usual value mean - 2standard deviation and the maximum usual value mean + 2standard deviation.
n = 150, p = 0.8
mean = 150*0.8 = 120
std = sqrt[120*0.2] = sqrt(24) = 2sqrt(6)
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Cheers,
Stan H.
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