SOLUTION: Find the z value such that P(-z < Z ,< z) = 0.95 (The greater than signs are supposed to be "greater than or equal to")
A. z = −1.645
B. z = −1.96
C. z
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-> SOLUTION: Find the z value such that P(-z < Z ,< z) = 0.95 (The greater than signs are supposed to be "greater than or equal to")
A. z = −1.645
B. z = −1.96
C. z
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You can put this solution on YOUR website! Find the z value such that P(-z <= Z <= z) = 0.95 (The greater than signs are supposed to be "greater than or equal to")
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With 95% centered on the mean, that leaves 2.25% in each tail.
Find the z-value with a left tail of 0.025::
-z = invNorm(0.025) = -1.96
z = 1.96
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Cheers,
Stan H.
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A. z = −1.645
B. z = −1.96
C. z = 1.645
D. z = 1.96
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