Question 805049: 500 people attended a birthday party. The men gave $5 each, the women $3 each and the kids I cent each. The total amount added up to $500
How many men gave $5? How many women gave $3 and how many kids gave 1 cent each
Found 2 solutions by richwmiller, ankor@dixie-net.com:
Answer by richwmiller(17219)   (Show Source):
You can put this solution on YOUR website! m+w+k=500,
5m+3w+.01k=500
there are either 100, 200, 300 or 400 kids
so k=100
m+w+100=500,
5m+3w+1=500
k=100 doesn't work
or k=200
m+w+200=500,
5m+3w+2=500
k=200 doesn't work
so k=300
m+w+300=500,
5m+3w+3=500
k=300 doesn't work
or k=400
m+w+400=500,
5m+3w+4=500
m=98, w=2, k=400
Answer by ankor@dixie-net.com(22740)  (Show Source):
You can put this solution on YOUR website! Write an equation for each statement
:
500 people attended a birthday party.
m + w + k = 500
:
The men gave $5 each, the women $3 each and the kids I cent each.
The total amount added up to $500
5m + 3w + .01k = 500
:
We got three unknown and two equations,
but we know the no. of kids has to be a multiple of 100, giving an even $ amt
Lets assume there are 400 kids, ($4) then the two equations will be
m + w = 100
and
5m + 3w = 496
Multiply the 1st equation by 5, subtract the above equation
5m + 5w = 500
5m + 3w = 496
--------------subtraction eliminates m, find w
2w = 4
w = 2 women gave $3 each
then
m + 2 = 100
m = 98 men giving $5 each
:
;
See if the adds up
5(98) + 3(2) + .01(400) =
490 + 6 + 4 = 500
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