SOLUTION: I need help with writing a sigma notation of 1/2 + 3/4 + 5/6 + ... 99/100, but I keep on getting lost and going in circles.

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Question 804988: I need help with writing a sigma notation of 1/2 + 3/4 + 5/6 + ... 99/100, but I keep on getting lost and going in circles.
Answer by AnlytcPhil(1806) About Me  (Show Source):
You can put this solution on YOUR website!
1/2 + 3/4 + 5/6 + ... 99/100
The denominators are the even natural numbers 2,4,6,8, and the pattern is 2n for n = 1,...,50

The numerators are 1 less than the denominators, 1,3,5,7, so we subtract 1
from that pattern 2n-1,

So the nth term is %282n-1%29%2F%282n%29, where n goes from 1 to 50, so we can write that as
 
sum%28%28%282n-1%29%2F%282n%29%29%2Cn=1%2C50%29

We can simplify, if desired:

%282n-1%29%2F%282n%29 = %282n%29%2F%282n%29%22%22-%22%221%2F%282n%29 = 1 - 1%2F%282n%29, so we write the summation as

sum%28%281-1%2F%282n%29%29%2Cn=1%2C50%29

and if we like we can distribute the summation as

 sum%28%281%29%2Cn=1%2C50%29%22%22-%22%22sum%28%281%2F%282n%29%29%2Cn=1%2C50%29

Then the first summation is just the sum of 50 ones, which is just 50.
So we can simplify it to

50%22%22-%22%22sum%28%281%2F%282n%29%29%2Cn=1%2C50%29

Edwin