SOLUTION: how do I determine the exact value of sin^2(-5π/6)?
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Question 804971
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how do I determine the exact value of sin^2(-5π/6)?
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lwsshak3(11628)
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determine the exact value of sin^2(-5π/6)
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(-5π/6) is in quadrant III where sin<0
reference angle = π/6
sin^2(-5π/6)=sin^2(π/6)=(-1/2)^2=1/4