SOLUTION: Question Find the exact solution to the equation in the interval [-2π, -3π/2]. sin (t) = sqrt(3)/2

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Question 804543: Question Find the exact solution to the equation in the interval [-2π, -3π/2].
sin (t) = sqrt(3)/2
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find the exact solution to the equation in the interval [-2π, -3π/2].
sin (t) = sqrt(3)/2
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Reference angle is in quadrant I where sin>0
sin(t)=√3/2
t=π/3