SOLUTION: I tried but I cant figure out asymptotes. please help? an easy to follow technique? I really want to learn. find the horizontal asymptote for f(x)= x^2+2x-3/x^2+4x+3

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: I tried but I cant figure out asymptotes. please help? an easy to follow technique? I really want to learn. find the horizontal asymptote for f(x)= x^2+2x-3/x^2+4x+3      Log On


   

Question 804410: I tried but I cant figure out asymptotes. please help? an easy to follow technique? I really want to learn.
find the horizontal asymptote for f(x)= x^2+2x-3/x^2+4x+3
Answer by erica65404(394) About Me  (Show Source):
You can put this solution on YOUR website!
f%28x%29=%28+x%5E2%2B2x-3%29%2F%28x%5E2%2B4x%2B3%29
For finding the horizontal, you want to look for the x with the highest degree for the numerator and denominator. Get rid of everything else
For this equation x%5E2%2Fx%5E2 is what we are looking at.
You find the horizontal, you need to start by plugging in numbers
You can plug in any number you want.
1%5E2%2F1%5E2=1
20%5E2%2F20%5E2=1
23456%5E2%2F23456%5E2=1
No matter what number you plug in, you will always get 1 so y=1 is your horizontal asymptote