Question 803895: question: a collection of nickels, dimes, and quarters consist of 15 coins with a total value of $1.10. If the number of nickels is one less than 4 times the number of dimes, how many of each coin are contained in the collection?
steps i took to begin the problem were:
quarters is q , nickels is n, and dimes is d
q + n + d = 15
.25q + .5n + .10d = 1.10
then for ' nickels is less than 4 times the # of dimes' i wrote n = 1 - 4d
how do i continue to solve the problem from there?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! question: a collection of nickels, dimes, and quarters consist of 15 coins with a total value of $1.10. If the number of nickels is one less than 4 times the number of dimes, how many of each coin are contained in the collection?
steps i took to begin the problem were:
quarters is q , nickels is n, and dimes is d
q + n + d = 15
.25q + .5n + .10d = 1.10
then for ' nickels is less than 4 times the # of dimes' i wrote n = 1 - 4d
how do i continue to solve the problem from there?
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Note:: n = 4d-1
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Equations:
n + d + q = 15 coins
5n+10d+25q = 110 cents
n - 4d + 0 = -1
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I used a matrix function on my TI-84 to get:
n = 11
d = 3
q = 1
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Cheers,
Stan H.
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