SOLUTION: the sum of the present age of father and his daughter is 42 years 7 years later the father will be 3 times old then the daughter the present age of the father is
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Question 803739: the sum of the present age of father and his daughter is 42 years 7 years later the father will be 3 times old then the daughter the present age of the father is Answer by erica65404(394) (Show Source):
You can put this solution on YOUR website! You know that the age of the daughter plus the age of the father is 42 years. You will use the equation x+y=42 (x=father y=daughter). When its 7 years later and the father will be 3 times the age of his daughter. Both the father and daughter will have aged 7 years so you would add 14 to 42 and now your equation will be x+y=56. you also need an equation to show that the father will be 3 times the age of his daughter. You would use 3y=x. now to figure out the fathers age you would need to plug 3y=x into x+y=56. 3y+y=56 we will use this to find the daughters age first. You will get y=14. The father will be 3 times the age of his daughter. You can now plug y=14 into 3y=x to find what the fathers age will be. You now know the fathers age will be 42 in 7 years. Since it is present day, simply subtract 7 from 42 to find his current age. The father is 35 years old.
