SOLUTION: How do I find two consecutive intergers such that twice the smaller is 10 more than 8 times the larger

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Question 803572: How do I find two consecutive intergers such that twice the smaller is 10 more than 8 times the larger
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive integers: x, (x+1)

2x = 8(x+1) + 10
2x = 8x + 18
-6x = 18
x = -3

The integers are -3 and -2.