SOLUTION: A square has a 40 cm diagonal. How long is each sine of the square. Round to the nearest tenth of a centimeter.
So far i have tried the Pythagorean theorem : {{{ a^2+b^2=40^2
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So far i have tried the Pythagorean theorem : {{{ a^2+b^2=40^2
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Question 803530: A square has a 40 cm diagonal. How long is each sine of the square. Round to the nearest tenth of a centimeter.
So far i have tried the Pythagorean theorem : a^2+b^2=40^2
40^2 = 1600 then since its a triangle both all the sides will be equal so i divided 1600 by 2 and get 800 i sqrt and got 28.2 but it doesnt equal. So can you explain to me how to do it and as well as give me the answer. Answer by rothauserc(4718) (Show Source):
