SOLUTION: Hooke's law. The distance d when a spring is streched by a hanging object varies directly as the weight w of the object. If the distance is 27cm when the weight is 4kg, what is the
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-> SOLUTION: Hooke's law. The distance d when a spring is streched by a hanging object varies directly as the weight w of the object. If the distance is 27cm when the weight is 4kg, what is the
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Question 803294: Hooke's law. The distance d when a spring is streched by a hanging object varies directly as the weight w of the object. If the distance is 27cm when the weight is 4kg, what is the distance when the weight is 5kg? The distance is cm. Please help! Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Hooke's law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object.
If the distance is 27cm when the weight is 4kg, what is the distance when the weight is 5kg? The distance is cm.
:
let d = dist when 5 kg is hung on the spring
Varies directly therefore: =
cross multiply
4d = 27 * 5
4d = 135
d = 135/4
d = 33.75 cm
