SOLUTION: michael has 58 coins totaling $4.40 all nickels dimes and quarters. the number of nickels is 2 short of being 3 times the sum of the number of dimes and quarters together how many
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-> SOLUTION: michael has 58 coins totaling $4.40 all nickels dimes and quarters. the number of nickels is 2 short of being 3 times the sum of the number of dimes and quarters together how many
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Question 803271: michael has 58 coins totaling $4.40 all nickels dimes and quarters. the number of nickels is 2 short of being 3 times the sum of the number of dimes and quarters together how many dimes are there Found 2 solutions by richwmiller, josmiceli:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! Let = number of nickels
Let = number of dimes
Let = number of quarters
----------------------------
(1)
(2) ( in cents )
(3)
-----------------------
(3)
(3)
Multiply both sides of (1) by
and add (1) and (3)
(1)
(3)
-----------
(2)
(2)
(2)
(2)
and
(3)
(3)
(3)
(3)
Subtract (3) from (2)
(2)
(3)
----------
(1)
(1)
(1)
(1)
There are 10 dimes
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check:
(2)
(2)
(2)
(2)
OK
