Question 803266: The sum of three numbers is -2. The sum of three times the first number, twice the second number, and the third number is 9. the difference between the second number and half the third number is 10. Find the numbers.
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! The sum of three numbers is -2. The sum of three times the first number, twice the second number, and the third number is 9. the difference between the second number and half the third number is 10. Find the numbers.
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x+y-z=-2
3x+2y+z=9
y-(z/2)=10
..
x+y-z=-2
3x+2y+z=9
2y-z=20
..
x+y+z=-2
3x+2y+z=9
subtract
-2x-y=-11
..
3x+2y+z=9
2y-z=20
add
3x+4y=29
..
-2x-y=-11
3x+4y=29
..
-8x-4y=-44
3x+4y=29
add
-5x=-15
x=3
y=-2x+11=5
z=2y-20=-10
..
numbers are: 2, 5, and -10
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