SOLUTION: what is the vertex of parabola y=x^2-6x+7?
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Question 803095
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what is the vertex of parabola y=x^2-6x+7?
Answer by
Alan3354(69443)
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what is the vertex of parabola y=x^2-6x+7?
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The vertex is on the Axis of Symmetry, which is x = -b/2a