SOLUTION: hat quantity of 80 percent acid solution must be mixed with a 20 percent solution to produce 600 mL of a 50 percent solution?

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Question 803059: hat quantity of 80 percent acid solution must be mixed with a 20 percent solution to produce 600 mL of a 50 percent solution?

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
L = 20%
T = 50%
H= 80%
u = how much of L
v = how much of H
M=600 mililiters of the 50%.

%28Lu%2BHv%29%2FM=T and u%2Bv=M

Solve for u and v, since the system is two equation in two unknowns, u and v.

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
hat quantity of 80 percent acid solution must be mixed with a 20 percent solution to produce 600 mL of a 50 percent solution?
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50 is the average of 80 and 20, so it's equal amounts.
300 ml of each.