SOLUTION: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts.

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Question 802663: Divide 72 in to two parts so that the larger part exceeds the smaller by 12 , find the both parts.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
if one part is x then other part will be x+12
Their sum = 72
x+x+12=72
2x+12=72
2x+12-12=72-12
2x=60
/2
2x/2 = 60/2
x=30
One part is 30 so the balance is 42 the other part