SOLUTION: Find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three.
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Question 802263
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Find four consecutive even integers such that four times the greatest is 36 more than the sum of the other three.
Answer by
CubeyThePenguin(3113)
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consecutive even integers: x, (x+2), (x+4), (x+6)
4(x+6) = 36 + (x + (x+2) + (x+4))
4x + 24 = 3x + 42
x = 18
integers: 18, 20, 22, 24