SOLUTION: Please help? These always confuse me.
Simplify.
x+2/x/x-2/3x
These are the ones that look like fractions on top of fractions.
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-> SOLUTION: Please help? These always confuse me.
Simplify.
x+2/x/x-2/3x
These are the ones that look like fractions on top of fractions.
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Question 80226: Please help? These always confuse me.
Simplify.
x+2/x/x-2/3x
These are the ones that look like fractions on top of fractions. Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Simplify.
x+2/x/x-2/3x
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Just remember: "invert the denominator and follow the rules of multiplication".
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Your Problem:
[(x+2)/x] / [(x-2)/3x]
=[(x+2)/x] * [3x/(x-2)]
Cancel the common factor of "x" to get:
=[3(x+2)/(x-2)]
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cheers,
Stan H.
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