Question 802181: In a quarter-pound bag of red pistachio nuts, some shells are too difficult to pry open by hand. Let the random variable X represent the number of pistachios in a randomly selected bag that cannot be opened by hand. The probability distribution for X is as follows: P(0)=0.500, P(1)=0.250, P(2)=0.100, P(3)=0.50, P(4)=0.075, P(5)=0.025
Find the mean (average) number of nuts per bag that cannot be opened by hand.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! The probability distribution for X is as follows: P(0)=0.500, P(1)=0.250, P(2)=0.100, P(3)=0.50, P(4)=0.075, P(5)=0.025
Find the mean (average) number of nuts per bag that cannot be opened by hand.
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mean = 0*0.5 + 1*0.25 + 2*0.10 + 3*0.5 + 4*0.075 + 5*0.025
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Note: At least one of your posted probabilities is wrong.
They add up to more than 1. I suspect your p(3) = 0.50 is wrong.
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Cheers,
Stan H.
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