SOLUTION: find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third

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Question 801938: find three consecutive positive integers such that the product of the first two is 22 less than 11 times the third
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive positive integers: (x-1), x, (x+1)

(x-1)(x) = 11(x+1) - 22
x^2 - x = 11x - 11
x^2 - 12x + 11 = 0
(x - 1)(x - 11) = 0
x = 1, x = 11

The integers are positive, so x = 11 and the integers are 10, 11, 12.