SOLUTION: We have recently started working with finding vertical asymptotes in class and I came across a problem in my homework that I am not sure how to approach. I have to find the vertica

Algebra ->  Functions -> SOLUTION: We have recently started working with finding vertical asymptotes in class and I came across a problem in my homework that I am not sure how to approach. I have to find the vertica      Log On


   

Question 801871: We have recently started working with finding vertical asymptotes in class and I came across a problem in my homework that I am not sure how to approach. I have to find the vertical asymptote of g(x)=(2x-1)(x+2)/(2x+3)(3x-4) If you could please help me I would appreciate it. Thanks
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
given: g%28x%29=%28%282x-1%29%28x%2B2%29%29%2F%28%282x%2B3%29%283x-4%29%29%29+
Vertical asymptote are zeros of denominator %28%282x%2B3%29%283x-4%29%29+.
set the denominator to zero and solve for x:
%282x%2B3%29%283x-4%29=0 ....it will be equal to zero if either %282x%2B3%29=0 or +%283x-4%29=0
if %282x%2B3%29=0=> 2x+=-3=> x+=-3%2F2=> x+=-1.5
if +%283x-4%29=0=>+3x=4=>+x=4%2F3=>=>+x=1.33