SOLUTION: An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have so

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have so      Log On


   

Question 80187: An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have sold them together for $1535 with a profit of 10% on the first and 25% on the other artwork. Find the actual cost of each artwork.
Found 2 solutions by stanbon, 572730:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
An art dealer sold two artworks for $1520 thereby making a profit of 25% on the first work and 10% profit on the other, whereas if he had approached any exhibition he would have sold them together for $1535 with a profit of 10% on the first and 25% on the other artwork. Find the actual cost of each artwork.
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Let x be the cost of the 1st work ; Let y be the cost of the 2nd work.
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EQUAIIONS:
1.25x+1.1y = 1520
1.1x+1.25y = 1535
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Use any method you know to solve this system of equations.
x=600 ; y=700
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Cheers,
Stan H.

Answer by 572730(2) About Me  (Show Source):