SOLUTION: The width of a rectangle is 10 inches less than its length. If the perimeter is 112 inches, find the dimensions of the rectangle.

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: The width of a rectangle is 10 inches less than its length. If the perimeter is 112 inches, find the dimensions of the rectangle.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 801333: The width of a rectangle is 10 inches less than its length. If the perimeter is 112 inches, find the dimensions of the rectangle.
Answer by waynest(281) About Me  (Show Source):
You can put this solution on YOUR website!
width (w) = L - 10
length (L) = L
p = 112
p = 2L + 2w
2L + 2(L - 10) = 112
2L + 2L - 20 = 112
4L - 20 + 20 = 112 + 20
4L = 132
4L/4 = 132/4
L = 33
check:
2(33) + 2(33 - 10) = 112
66 + 2(23) = 112
66 + 46 = 112
112 = 112