SOLUTION: What are the critical values of y'=x^3-x^2?
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Question 801330
:
What are the critical values of y'=x^3-x^2?
Answer by
tommyt3rd(5050)
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y''=3x^2-2x
y''=0 implies
x(3x-2)=0
leads to x=0 or x=2/3
use these values of x in y' to get critical values:
y'(2)=8-4=4
y'(2/3)=8/27-4/9=-4/27