SOLUTION: If a sample distribution has a mean of 48 and a standard deviation of 6, the probability of obtaining a score between 42 and 54 is _____?_

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Question 801051: If a sample distribution has a mean of 48 and a standard deviation of 6, the probability of obtaining a score between 42 and 54 is _____?__ and the Z-score of a student who scored 36 is _2____

Please provide answer and formula for obtaining the answer. Also I calculated the result for the Z score - is the Z score of 2 correct?
Thanks

Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website!
we are asked to calculate the probability that score lies between 42 and 54, we do this by calculating Pr(X<54)and Pr(X<42), then Pr(X<54) - Pr(X<42) = Pr(42 z-score for Pr(X<54) = (54-48)/6 = 1
z-score for Pr(X<42) = (42-48)/6 = -1
now consult the z-tables for the corresponding probabilities
Pr(X<54) = .8621
Pr(X<42) = .1587
Probability that score lies between 42 and 54 = .8621 - .1587 = .7034 = .70
z-score for a student who scored 36 = (36-48) / 6 = -2

SOLUTION: If a sample distribution has a mean of 48 and a standard deviation of 6, the probability of obtaining a score between 42 and 54 is _____?__ and the Z-score of a student who scored

SOLUTION: If a sample distribution has a mean of 48 and a standard deviation of 6, the probability of obtaining a score between 42 and 54 is ___? and the Z-score of a student who scored