SOLUTION: Calculate the following problem: suppose you offered to put a penny into your child’s piggy bank. Then, each day forward you put in double the amount from the previous day. How man

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Question 800855: Calculate the following problem: suppose you offered to put a penny into your child’s piggy bank. Then, each day forward you put in double the amount from the previous day. How many days would it take to make $100,000? (Day 1 = 1 penny, Day 2 = 2 pennies, Day 3 = 4 pennies, Day 4 = 8 pennies, Day 5 = 16 pennies, Day 6 = 32 pennies, and so on) Remember to add the contribution from each previous day to find the total amount of pennies at the end of the day. (Day 2 = total 3 pennies, Day 3 = total 7 pennies, and so on)

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
$100,000 is 10,000,000 pennies, which I can write as 10%5E7 pennies.
The numbers of pennies added to the child's piggy bank form a geometric sequence.
In a geometric sequence with first term b%5B1%5D and common ratio r
the general form for term number n is b%5Bn%5D=b%5B1%5D%2Ar%5E%28n-1%29,
and the sum of the first n terms can be calculated as
S%5Bn%5D=b%5B1%5D%28r%5En-1%29%2F%28r-1%29
In this case b%5B1%5D=1 and r=2, so
S%5Bn%5D=1%2A%282%5En-1%29%2F%282-1%29=1%2A%282%5En-1%29%2F1=2%5En-1
For S%5Bn%5D=10%5E8 we need 2%5En-1-1=10%5E8, which we can state as 2%5En%3E10%5E8
I happen to know that 2%5E10=1024
That means that 2%5E20=2%5E%2810%2A2%29=%282%5E10%29%5E2=1024%5E2=1048576=1.048576%2A10%5E6%3C10%5E7
so after 20 days the child's piggy bank would not have $100,000.

so after 23 days the child's piggy bank would not have $100,000.

so the child's piggy bank would get over $100,000 on day highlight%2824%29

NOTE:
I just weighed 50 pennies, and got a weight of 131 g, so 100=10%5E2 pennies would weigh about 260 g = 0.26 kg.
Then 10%5E7=10%5E2%2A10%5E5 pennies would weigh about 0.26%2A10%5E5=26%2A10%5E3kg.
That's 26 metric tons. You would need a large truck to carry that many pennies.