SOLUTION: Prove that tan(10°)cos(20°)tan(40°)tan(50°)csc(70°)sec(80°)sin(80°) = 1

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Question 800722: Prove that tan(10°)cos(20°)tan(40°)tan(50°)csc(70°)sec(80°)sin(80°) = 1
Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
Prove that tan(10°)cos(20°)tan(40°)tan(50°)csc(70°)sec(80°)sin(80°) = 1

Change all trig ratios other than the sines and cosines
to sines and cosines, and put 1 denominators under the 
sines and cosines, using these quotient and reciprocal 
identities: 

tan%28theta%29%29%22%22=%22%22sin%28theta%29%2Fcos%28theta%29, sec%28theta%29%22%22=%22%221%2Fcos%28theta%29, csc%28theta%29%22%22=%22%221%2Fsin%28theta%29

sin%28%2210%B0%22%29%2Fcos%28%2210%B0%22%29%22%22%2A%22%22cos%28%2220%B0%22%29%2F1%22%22%2A%22%22sin%28%2240%B0%22%29%2Fcos%28%2240%B0%22%29%22%22%2A%22%22sin%28%2250%B0%22%29%2Fcos%28%2250%B0%22%29%22%22%2A%22%221%2Fsin%28%2270%B0%22%29%22%22%2A%22%221%2Fcos%28%2280%B0%22%29%22%22%2A%22%22sin%28%2280%B0%22%29%2F1%22%22%2A%22%22

Next change all the cosines to sines using the cofuction identity:

cos%28theta%29%22%22=%22%22sin%28%2290%B0%22-theta%29

cos%28%2210%B0%22%29%22%22=%22%22sin%28%2290%B0%22-%2210%B0%22%29%22%22=%22%22sin%28%2280%B0%22%29
cos%28%2220%B0%22%29%22%22=%22%22sin%28%2290%B0%22-%2220%B0%22%29%22%22=%22%22sin%28%2270%B0%22%29
cos%28%2240%B0%22%29%22%22=%22%22sin%28%2290%B0%22-%2240%B0%22%29%22%22=%22%22sin%28%2250%B0%22%29
cos%28%2250%B0%22%29%22%22=%22%22sin%28%2290%B0%22-%2250%B0%22%29%22%22=%22%22sin%28%2240%B0%22%29
cos%28%2280%B0%22%29%22%22=%22%22sin%28%2290%B0%22-%2280%B0%22%29%22%22=%22%22sin%28%2210%B0%22%29

Substitute those for all the cosines:

sin%28%2210%B0%22%29%2Fsin%28%2280%B0%22%29%22%22%2A%22%22sin%28%2270%B0%22%29%2F1%22%22%2A%22%22sin%28%2240%B0%22%29%2Fsin%28%2250%B0%22%29%22%22%2A%22%22sin%28%2250%B0%22%29%2Fsin%28%2240%B0%22%29%22%22%2A%22%221%2Fsin%28%2270%B0%22%29%22%22%2A%22%221%2Fsin%28%2210%B0%22%29%22%22%2A%22%22sin%28%2280%B0%22%29%2F1%22%22%2A%22%22

That all cancels and gives 1

Edwin