SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 5 days. Write a function B(d) that represents the amount

Algebra ->  Exponents -> SOLUTION: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 5 days. Write a function B(d) that represents the amount      Log On


   



Question 800650: A population of bacteria has 1175 bacteria in its starting population. The half-life of this particular type of bacteria is 5 days. Write a function B(d) that represents the amount of bacteria B in the population after d days.
B(d)=
I've tried 1175(.5)^d and 1175(5)^d but can't seem to figure it out.

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
A population of bacteria has 1175 bacteria in its starting population.
The half-life of this particular type of bacteria is 5 days.
Write a function B(d) that represents the amount of bacteria B in the population after d days.
:
B%28d%29=+1175%2A2%5E%28-d%2F5%29; that's -d%2F5