SOLUTION: write the equation for the line in y=mx+b form that is perpendicular to the line with equation y=-4/3x-4 that passes through the point (-5,6)
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Question 800183: write the equation for the line in y=mx+b form that is perpendicular to the line with equation y=-4/3x-4 that passes through the point (-5,6) Answer by Cromlix(4381) (Show Source):
You can put this solution on YOUR website! Lines that are perpendicular to one
another have slopes that multiply
together to give -1
m1 * m2 = -1
y = -4/3x-4 has a slope of -4/3
-4/3 * m2 = -1
m2 = 3/4.
Using the slope 3/4 and the coordinates (-5,6)
y = mx + c
6 = 3/4(-5) + c
6 = -15/4 + c
c = 6 + 15/4
c = 39/4
Equation is:
y = 3/4x + 39/4
OR multiply through by 4
4y = 3x + 39.
Hope this helps.
:-)
