SOLUTION: Can you solve a system of equations of 4=a(b)^0 1=a(b)^2

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Question 800014: Can you solve a system of equations of
4=a(b)^0
1=a(b)^2
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
4=a(b)^0
1=a(b)^2

b^0=1
therefore a=4
1=a(b)^2
1=4(b)^2
1/4 = b^2
b= +/-(1/2)