Question 799831: How would you solve these problems.
x+3y-8=0, 2x-3y=-8
2/3x-4/3y=2, .03x-.02y=.1
y+2x=3, 5x+2y-12=0
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! How would you solve these problems.
x+3y-8=0, 2x-3y=-8
2/3x-4/3y=2, .03x-.02y=.1
y+2x=3, 5x+2y-12=0
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I would use elimination.
Add the 1st pair.
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For the 2nd, multiply the 1st eqn by 3 and the 2nd by 200, then subtract.
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