SOLUTION: <pre>Suppose S and T are mutally exclusive. P(S)=6% P(T)= 29% (1) Find P(S and T) (2) Find P(S or T)</pre>

Algebra ->  Probability-and-statistics -> SOLUTION: <pre>Suppose S and T are mutally exclusive. P(S)=6% P(T)= 29% (1) Find P(S and T) (2) Find P(S or T)</pre>       Log On


   

Question 79980: 
Suppose S and T are mutally exclusive. 

P(S)=6%  P(T)= 29%

(1)  Find P(S and T)
(2)  Find P(S or T)
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!
suppose S and T are mutally exclusive. 

P(S)=6%  P(T)= 29%

(1)  Find P(S and T)

Since they are mutually exclusive, they cannot both
occur at the same time.  

So P(S and T) is the probability of an impossible
event, so P(S and T) = 0

---------------------------------------------------

(2)  Find P(S or T)

P(S or T) = P(S) + P(T) - P(S and T)

P(S or T) = .06 + .29 - 0 

P(S or T) = .35 = 35%

Edwin