SOLUTION: Ed can do a job in 4 days. When Ed and Maymay work together, it would take them 2 1/3 days. How long would the job take Maymay to do the job alone?

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Ed can do a job in 4 days. When Ed and Maymay work together, it would take them 2 1/3 days. How long would the job take Maymay to do the job alone?      Log On


   



Question 799691: Ed can do a job in 4 days. When Ed and Maymay work together, it would take them 2 1/3 days. How long would the job take Maymay to do the job alone?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Ed can do a job in 4 days.
When Ed and Maymay work together, it would take them 2 1/3 days.
How long would the job take Maymay to do the job alone?
:
Let m = May^2 time to do the job alone
let the completed job = 1
Change 2 1/3 days to 7/3
:
A shared work equation
%287%2F3%29%2F4 + %287%2F3%29%2Fm = 1
Which is
7%2F12 + 7%2F%283m%29+ = 1
multiply by 12m, resulting in
7m + 4(7) = 12m
28 = 12m - 7m
28 = 5m
m = 28/5
m = 53%2F5 days May^2 alone