SOLUTION: when all n teams in a league play every other team twice, a total N games are played, where N= n^2-n. A soccer league has 8 teams and all play each other twice. How many games are

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Question 799362: when all n teams in a league play every other team twice, a total N games are played, where N= n^2-n. A soccer league has 8 teams and all play each other twice. How many games are played?
Found 2 solutions by thejackal, stanbon:
Answer by thejackal(72) About Me  (Show Source):
You can put this solution on YOUR website!
f(N) = n^2-n
substitute
f(N) = 8^2-8
f(N) = number of games = 56

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
when all n teams in a league play every other team twice, a total N games are played, where N= n^2-n. A soccer league has 8 teams and all play each other twice. How many games are played?
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N = 8^2-8 = 64-8 = 56 games
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Cheers,
Stan H.
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