SOLUTION: The lenght of a rectangular floor is 8 feet greater that its width . If each dimension is Increased by two Feet, The Area Is increased by 60 feet^2 . Find the dimensions of the f

Algebra ->  Rectangles -> SOLUTION: The lenght of a rectangular floor is 8 feet greater that its width . If each dimension is Increased by two Feet, The Area Is increased by 60 feet^2 . Find the dimensions of the f      Log On


   

Question 799239: The lenght of a rectangular floor is 8 feet greater that its width . If each dimension is Increased by two Feet, The Area Is increased by 60 feet^2 . Find the dimensions of the floor.
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
width =x
length = (x+8)

Original area = x(x+8) sq.ft
Increase the dimensions by 2 feet
width = (x+2)
length = (x+10)
Area = (x+2)(x+10)
(x+2)(x+10)-x(x+2)=60
(x+2)(x+10-x)=60
10(x+2)=60
10x+20=60
10x=40
x=4
width = 4 and length = 4+8 =12 feet