SOLUTION: If the side of a cube increases in size by 9%, then by what percentage does the surface area increase?

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Question 799050: If the side of a cube increases in size by 9%, then by what percentage does the surface area increase?
Found 2 solutions by Finavon, stanbon:
Answer by Finavon(81) About Me  (Show Source):
Answer by stanbon(75887) About Me  (Show Source):
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If the side of a cube increases in size by 9%, then by what percentage does the surface area increase?
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Original surface area = 6s^2 where "s" is the length of a side.
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New surface area = 6(1.09s)^2 = 7.1286s^2
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Quantitative gain: 1.1286s^2
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% gain: 1.1286s^2/6s^2 = 0.1881 = 18.81%
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Cheers,
Stan H.
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