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Question 79886: write the equation in slop=intercept form of the line that passes through the points
13. (5,-6) (1,-7) 14. (6,-3) (-1,9)
Answer by checkley75(3666)   (Show Source):
You can put this solution on YOUR website! 13) SLOPE=(Y2-Y1)/(X2-X1), (-7+6)/(1-5), -1/-4, 1/4 IS THE SLOPE.
NOW SUBSTITUTE 1 SET OF (X,Y) POINTS WITH THE SLOPE(m) & SOLVE FOR THR Y INTERCEPT (b) IN THE LINE SEQUATION Y=mX+b.
-6=1/4*5+b
-6=5/4+B
b=-6-5/4
b=-27/4
THUS THE EQUATION FOR A LINE THROUGH THESE POINTS IS:
Y=X/4-27/4 [THIS IS THE RED LINE ON THE GRAPH]
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SLOPE=(-3-9)/(6+1)
-12/7 IS THE SLOPE
-3=-12/7*6+b
-3=-72/7+b
b=-3+72/7
b=(-21+72)/7
b=51/7
SO THE EQUATION FOR THIS LINE IS
Y=-12X/7+51/7 [THIS IS THE GREEN LINE ON THE GRAPH]
 (graph 300x200 pixels, x from -6 to 30, y from -10 to 10, of TWO functions y = x/4 -27/4 and y = -12x/7 +51/7 ).
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