SOLUTION: find the probability p(e or f) if e and f are mutually exclusive, P(E)=0.25, and P(F)=0.47

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Question 798772: find the probability p(e or f) if e and f are mutually exclusive, P(E)=0.25, and P(F)=0.47
Answer by stanbon(75887) About Me  (Show Source):
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find the probability p(e or f) if e and f are mutually exclusive, P(E)=0.25, and P(F)=0.47
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If e and f are mutually exclusive P (e AND f) = 0
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P(e OR f) = P(e) + P(f) - P(e AND f)
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P(e OR f) = 0.25 + 0.47 - 0
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= 0.72
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Cheers,
Stan H.
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