SOLUTION: Log(base4)(2x+1)=Log(base4)(x-3)+Log(base4)(x+5)

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Question 79876: Log(base4)(2x+1)=Log(base4)(x-3)+Log(base4)(x+5)
Answer by Nate(3500) About Me  (Show Source):
You can put this solution on YOUR website!
log%284%2C2x+%2B+1%29+=+log%284%2Cx+-+3%29+%2B+log%284%2Cx+%2B+5%29
log%284%29%282x+%2B+1%29+=+log%284%2C%28x+-+3%29%28x+%2B+5%29%29
log%284%29%282x+%2B+1%29+=+log%284%2Cx%5E2+%2B+2x+-+15%29
2x+%2B+1+=+x%5E2+%2B+2x+-+15
0+=+x%5E2+-+16
0+=+%28x+%2B+4%29%28x+-+4%29
x = -4 and x = 4
You can not take a log of a negative number. Answer: x = 4