SOLUTION: Solve for x. Log base 9 (x-6) + log base 9 (x+2)=1

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Question 798460: Solve for x.
Log base 9 (x-6) + log base 9 (x+2)=1
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for x.
Log base 9 (x-6) + log base 9 (x+2)=1
log%289%2C%28x-6%29%29%2Blog%289%2C%28x%2B2%29%29=1
log%289%2C%28%28x-6%29%28x%2B2%29%29%29=1
convert to exponential form: (base(9) raised to log of number(1)=number(x-6)(x+2)
9^1=(x-6)(x+2)
9=x^2-4x-12
x^2-4x-21=0
(x+3)(x-7)=0
x=-3(reject,(x-6)>0)
or
x=7