SOLUTION: The length of a rectangle is 4 units longer than twice its width. If the perimeter of the rectangle is 62, how long is each side?
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Question 798407: The length of a rectangle is 4 units longer than twice its width. If the perimeter of the rectangle is 62, how long is each side? Answer by 2897696(96) (Show Source):
You can put this solution on YOUR website! VARIABLES:
let the width of the rectangle = x
let length= 4+2x
since you are finding the perimeter of the rectangle, the formula is
length + length + width + width = perimeter ==> 2(length)+2(width)= perimeter
plug in variables for length and width.
2x+2(4+2x)=62
2x+8+4x=62
6x+8=62 (subtract 8 from both sides)
6x=54 (divide doth sides by 6)
x=9
so the width is 9
length is 4+2x ==> 4+2(9) ==> 22
answer: width 9 length 22
check:
9+9+22+22=62
18+44=62
62=62
