SOLUTION: An explorer hikes 4 miles due east, 7 miles due south, then 3 miles due east, then 1 mile due north, and finally 2 miles due west. How far is he from his original position? (This i

Algebra ->  Length-and-distance -> SOLUTION: An explorer hikes 4 miles due east, 7 miles due south, then 3 miles due east, then 1 mile due north, and finally 2 miles due west. How far is he from his original position? (This i      Log On


   



Question 798196: An explorer hikes 4 miles due east, 7 miles due south, then 3 miles due east, then 1 mile due north, and finally 2 miles due west. How far is he from his original position? (This is a pythagorean theorem problem)
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
Here's a map showing the explorer's path.
Each square in the grid is 1 mile by 1 mile.
The explorer goes along the red arrow path from point A to point B.
The distance (as the crow flies) from A to B is the hypotenuse (AB) of the green right triangle ABC.
AC=6 and CB=5 so AB%5E2=6%5E2%2B5%5E2=36%2B25=61--> AB=sqrt%2861%29 is about 7.8 miles.

NOTE:
Without drawing the map, we could calculate total distance to the East as the sum of the eastward stretches of the path:
4%2B3%2B%28-2%29=5.
Similarly, we could calculate total distance to the South as the sum of the southward stretches of the path:
7%2B%28-1%29=6.