SOLUTION: A concrete walk of uniform width is to be built around a circular pool, as shown in the figure. The radius of the pool is 16 meters, and enough concrete is available to cover $ {

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Question 798186: A concrete walk of uniform width is to be built around a circular pool, as shown in the figure. The radius of the pool is 16 meters, and enough concrete is available to cover $ {\color{black}144} \pi $ square meters. If all the concrete is to be used, how wide should the walk be?
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
PROBABLE EXPECTED SOLUTION:
The area of the pool is the area of a circle of radius 16m, so it is
pi%2A16%5E2m%5E2=256pim%5E2
The area (in square meters) of the pool plus a surrounding walkway of width x meters would be the area of a circle of radius 16%2Bx meters:

The difference is the area of the walkway. In square meters, it is
256pi%2Bpi%2832x%2Bx%5E2%29-256pi=%2832x%2Bx%5E2%29pi
If we can use enough concrete to cover 144pi square meters,
%2832x%2Bx%5E2%29pi=144pi
and x%5E2%2B32x=144 is our equation.
We can solve it by completing the square, by factoring, or by using the quadratic formula.

Completing the square:
x%5E2%2B32x=144
x%5E2%2B32x%2B16%5E2=144%2B16%5E2
%28x%2B16%29%5E2=144%2B254
%28x%2B16%29%5E2=400
%28x%2B16%29%5E2=20%5E2
Since we are looking for a positive number x,
x=16=20 --> x=20-16 --> highlight%28x=4%29

Factoring:
x%5E2%2B32x=144
x%5E2%2B32x-144=0
%28x-4%29%28x%2B36%29=0 --> x-4=0 --> highlight%28x=4%29
because x%2B36=0 <--> x=-36 is not an acceptable solution.

Applying the quadratic formula:
The solutions to +ax%5E2%2Bbx%2Bc=0 are given by x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
In the case of x%5E2%2B32x-144=0, a=1, b=32, and c=-144, so

The two solutions are
x=%28-32-40%29=2=-72%2F2=-36 which does not make sense as width of a walkway,
and x=%28-32%2B40%29%2F2=8%2F2=highlight%284%29 which is the width, in meters, of the walkway we want.

MENTAL MATH QUICK SOLUTION:
The area of a circle or radius R is pi%2AR%5E2
The area of the pool, pi%2A16%5E2 square meters,
plus the area of the walkway, pi%2A144=pi%2A12%5E2 square meters,
adds up to the area, pi%2AR%5E2, of a larger circle of radius R meters. So pi%2A16%5E2%2Bpi%2A12%5E2=pi%2AR%5E2 --> 16%5E2%2B12%5E2=R%5E2
That reminds me of the Pythagorean theorem.
Since 16=4%2A4 and 12=4%2A3, I can think of 16%5E2%2B12%5E2=R%5E2 as
%284%2A4%29%5E2%2B%284%2A3%29%5E2=R%5E2 --> 4%5E2%2A4%5E2=4%5E2%2A3%5E2=R%5E2 --> 4%5E2%284%5E2%2B3%5E2%29=R%5E2
Since 4%5E2%2B3%5E2=16%2B9=25=5%5E2 has been used in so many problems, I remember it better than I remember the times tables, so
4%5E2%284%5E2%2B3%5E2%29=R%5E2 --> 4%5E2%2A5%5E2=R%5E2 --> %284%2A5%29%5E2=R%5E2 --> R=20
and that means that the width of the sidewalk is 20-16=highlight%284%29 meters