SOLUTION: Consider
4x+tx−20y = 0
x−4y+ty = 0
Find an expression for the determinant of the coefficient matrix A of this system.
det(A) = ?
Use your previous an
Algebra ->
Matrices-and-determiminant
-> SOLUTION: Consider
4x+tx−20y = 0
x−4y+ty = 0
Find an expression for the determinant of the coefficient matrix A of this system.
det(A) = ?
Use your previous an
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Question 798071: Consider
4x+tx−20y = 0
x−4y+ty = 0
Find an expression for the determinant of the coefficient matrix A of this system.
det(A) = ?
Use your previous answer to give the solutions for x and y of this system for all real values of t.
x= ? and x= ?
*** My problem is that I don't understand how to begin it. We usually work with 3*3 or 4*4 matrices in class.
Thank You,
Cristina Answer by Edwin McCravy(20060) (Show Source):
There is obviously a trivial solution x=0, y=0,
in which t can be any number. So for any other
case we will assume there are other soluitions.
For
4x+tx-20y = 0
Factor x out of the first two terms on the left
x(4+t) - 20y = 0
(4+t)x - 20y = 0
For
x-4y+ty = 0
Factor -y out of the last two terms on the left
x-y(4-t) = 0
x-(4-t)y = 0
So the system of equations is
(4+t)x - 20y = 0
x - (4-t)y = 0
Since both constant terms on the right are 0,
that means the determinant of coefficient
matrix must be 0, so
det(A) = 0
Evaluate the determinant on the left and we have
-(4+t)(4-t) - (-20)(1) = 0
-(16-t²) + 20 = 0
-(16-t²) = -20
16-t² = 20
-t² = 4
t² = -4
t = ±√-4
t = ±2i
Oh, oh!!!!! Something is wrong with the problem!!!!!
There are no real values of t!!!!!
You must have copied a sign or number wrong, for t
cannot be a real number as the problem is given
here, except for the one trivial solution x=0 and
y=0, in which case t can be any number.
If you will state the problem correctly in the
thank-you note form, we can help you. Be sure to
check the signs and numbers very carefully.
Edwin