SOLUTION: Can you please help me solve this simultaneous equation by substitution method? x+y=0.5 x-y=1

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Question 798014: Can you please help me solve this simultaneous equation by substitution method?
x+y=0.5
x-y=1

Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
system%28x%2By=0.5%2Cx-y=1%29

To solve a system of equations by substitution, you start by solving one of the equations for one of the variables.
In this case, we could solve x-y=1 for x:
x-y=1-->x=y%2B1

Next, you substitute the expression found for that variable into the other equation.
In this case, we replace y%2B1 for x in x%2By=0.5 to get
y%2B1%2By=0.5

Then, you simplify and solve the resulting equation:
y%2B1%2By=0.5-->2y%2B1=0.5-->2y=0.5-1-->2y=-0.5-->y=-0.5%2F2-->highlight%28y=-0.25%29

Finally, you go back to the equation initially "solved" and plug in the value found:
Plugging y=-0.25 into x=y%2B1 we find
x=-0.25%2B1-->highlight%28x=0.75%29

The solution to the system of equations is
highlight%28system%28x=0.75%2Cy=-0.25%29%29

It is good practice to verify that your solution is correct by plugging the numbers found into the original equations.
Sometimes the problem instructions tell you to check that way.
Plugging x=0.75 and y=-0.25 into x%2By=0.5 we find
0.75%2B%28-0.25%29=0.5<-->0.75-0.25=0.5, which is true.
Plugging the solution found into x-y=1 we find
0.75-%28-0.25%29=1<-->0.75%2B0.25=1, which is also true.
Now we know that the solution found is correct. We did not make a mistake.

NOTE:
It is not always that easy. To start, you should choose wisely what variable to solve for. Look for a variable that has no visible coefficient in front.
Otherwise, you may end up working with fractions, and it is more likely to make a mistake.
If the system is system%283x%2By=4%2C7x-2y=5%29,
the easiest way to start is to solve 3x%2By=4 for y:
3x%2By=4-->y=4-3x.