SOLUTION: Solve algebraically cos^2 x = sin x to find solutions in the domain 0<= x < 2 pi

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Question 797886: Solve algebraically cos^2 x = sin x to find solutions in the domain 0<= x < 2 pi
Answer by lwsshak3(11628) About Me  (Show Source):
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Solve algebraically cos^2 x = sin x to find solutions in the domain 0<= x < 2 pi
cos^2 x = sin x
1-sin^2 x=sin x
sin^2 x+sin x-1=0
solve for sin x by quadratic formula:
sin+x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
a=1, b=1, c=-1
sin x=-1.618 (reject, -1 < sin x < 1)
or
sin x=0.618
x≈0.6661