SOLUTION: The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width, what are the dimensions? L=102/2W-15

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Question 797693: The perimeter of a rectangle is 102 cm. If the length is 15 cm less than twice the width, what are the dimensions?
L=102/2W-15
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
L length, W width.
L=-15+2W

2L%2B2W=2%282W%2B15%29%2B2W=102
4W%2B30%2B2W=102
6W%2B30=102
6W=102-30
6W=72
W=6
.
and L....?